C++-循环嵌套-鸡兔同笼
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Background
Description
鸡兔同笼，共有35个头，94只脚，求鸡和兔子各多少只？ 设鸡有x只，兔子有y只，由题意得方程组 x+y=35 2x+4y=94 联立解得x = 23, y = 12 试用程序实现上述过程，输入头与脚的数量，算出鸡和兔子的只数
Format
Input
Output
Samples
35
94
23 12
Limitation
1s, 1024KiB for each test case.
鸡兔同笼（不同的题型）
- Status
- Done
- Rule
- ACM/ICPC
- Problem
- 15
- Start at
- 2024-5-15 17:00
- End at
- 2024-5-24 1:00
- Duration
- 200 hour(s)
- Host
-
吴泽宏 (wuzehong)
- Partic.
- 17